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HLSL: Validate implicit initializer assignment to opaque members.

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Fixes #1091.
This commit is contained in:
John Kessenich 2017-10-07 13:23:09 -06:00
parent 07ed11f9a0
commit bb79abccb3
2 changed files with 17 additions and 4 deletions
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9
hlsl/hlslGrammar.cpp
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@ -2426,6 +2426,9 @@ bool HlslGrammar::acceptDefaultParameterDeclaration(const TType& type, TIntermTy
node = parseContext.handleFunctionCall(token.loc, constructor, node);
}
if (node == nullptr)
return false;
// If this is simply a constant, we can use it directly.
if (node->getAsConstantUnion())
return true;
@ -2862,7 +2865,7 @@ bool HlslGrammar::acceptUnaryExpression(TIntermTyped*& node)
parseContext.handleFunctionArgument(constructorFunction, arguments, node);
node = parseContext.handleFunctionCall(loc, constructorFunction, arguments);
return true;
return node != nullptr;
} else {
// This could be a parenthesized constructor, ala (int(3)), and we just accepted
// the '(int' part. We must back up twice.
@ -3072,7 +3075,7 @@ bool HlslGrammar::acceptConstructor(TIntermTyped*& node)
// hook it up
node = parseContext.handleFunctionCall(arguments->getLoc(), constructorFunction, arguments);
return true;
return node != nullptr;
}
return false;
@ -3120,7 +3123,7 @@ bool HlslGrammar::acceptFunctionCall(const TSourceLoc& loc, TString& name, TInte
// call
node = parseContext.handleFunctionCall(loc, function, arguments);
return true;
return node != nullptr;
}
// arguments