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GLSL: Fix #1358: Support "struct name", where name could be a user type

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This commit is contained in:
John Kessenich 2018-06-11 19:25:24 -06:00
parent 1ea8f595f9
commit 2c8265bb62
4 changed files with 56 additions and 5 deletions
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9
glslang/MachineIndependent/Scan.cpp
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@ -778,7 +778,7 @@ int TScanContext::tokenize(TPpContext* pp, TParserToken& token)
case '?': return QUESTION;
case '[': return LEFT_BRACKET;
case ']': return RIGHT_BRACKET;
case '{': return LEFT_BRACE;
case '{': afterStruct = false; return LEFT_BRACE;
case '}': return RIGHT_BRACE;
case '\\':
parseContext.error(loc, "illegal use of escape character", "\\", "");
@ -861,7 +861,6 @@ int TScanContext::tokenizeIdentifier()
case IN:
case OUT:
case INOUT:
case STRUCT:
case BREAK:
case CONTINUE:
case DO:
@ -874,6 +873,10 @@ int TScanContext::tokenizeIdentifier()
case CASE:
return keyword;
case STRUCT:
afterStruct = true;
return keyword;
case NONUNIFORM:
if (parseContext.extensionTurnedOn(E_GL_EXT_nonuniform_qualifier))
return keyword;
@ -1537,7 +1540,7 @@ int TScanContext::identifierOrType()
return IDENTIFIER;
parserToken->sType.lex.symbol = parseContext.symbolTable.find(*parserToken->sType.lex.string);
if (afterType == false && parserToken->sType.lex.symbol) {
if ((afterType == false && afterStruct == false) && parserToken->sType.lex.symbol != nullptr) {
if (const TVariable* variable = parserToken->sType.lex.symbol->getAsVariable()) {
if (variable->isUserType()) {
afterType = true;